Just a simple trick question to see if guys are on their toes [?] public class Test { public static void main(String[] args) { int n = 0; for (int m = 0; m < 5; m++) { n = n++; System.out.println(n); } } } Output: 0 0 0 0 0 Why? Who will be first to answer correctly? -- Regards Brian Ngure
Easy. It's because you assign n to itself before you increment it. The expected way would be simply n++; instead of n = n++; To give you the output of 1 2 3 4 5
Right. Quite simple. But I saw this question on a forum and the guy just could not get it. Makes you wonder.... On Thu, May 26, 2011 at 9:08 PM, Haggai Nyang <haggai.nyang@gmail.com>wrote:
Easy. It's because you assign n to itself before you increment it. The expected way would be simply
n++;
instead of
n = n++;
To give you the output of
1 2 3 4 5
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-- Regards Brian Ngure
However, that's noob coding, I'd refactor that to something like: int n = 0; while(n <= 5) { System.out.println(++n); }
Yes. No reason to use two variables. Also, not know that n++ is a post increment is a bit green. On Thu, May 26, 2011 at 9:18 PM, Haggai Nyang <haggai.nyang@gmail.com>wrote:
However, that's noob coding, I'd refactor that to something like:
int n = 0; while(n <= 5) { System.out.println(++n); }
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-- Regards Brian Ngure
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Brian Ngure -
Haggai Nyang