Sorry i meant the moment the condition it returns false (when i => 8) the loop is done. -Billy 2009/6/22 Billy <billyx5@gmail.com>
i < 8 is the condition being evaluated so the moment it returns true (when i == 7) thats it. j has no influence on the evaluation of this condition. its same as if you had done
main()
{ int i, j;
for (i=0, j=1; i<8; i++) { printf("%d - %d = %d\n", j, i, j - i); *j++;* } return 0; }
-Billy
2009/3/22 Rahim Kara <rahim@applecentre.co.ke>
It's a basic question and i'm sure alot of you can answer this but i'm
still a bit sure. Take a look at the code below.
#include <stdio.h>
main()
{ int i, j;
for (i=0, j=1; i<8; i++, j++)
printf("%d - %d = %d\n", j, i, j - i); return 0; }
Now the results yielded are
1 - 0 = 1 2 - 1 = 1 ... 8 - 7 = 1
i'd like to know what the delimiting factor here is, i.e. considering i've not set a loop limit for j, what's stopping my calculation from being as follows..
148 - 8 = 0
as an example though from my understanding, it should present an infinite loop.
I\ve been pondering this a while, thought i'd get some Guru's out there to help out with my understanding of this.
Rahim.
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